A+B for Input-Output Practice (IV)
时间： 1ms 内存：64M
描述：
Your task is to Calculate the sum of some integers.
输入：
Input contains multiple test cases. Each test case contains a integer N, and then N integers follow in the same line. A test case starting with 0 terminates the input and this test case is not to be processed.
输出：
For each group of input integers you should output their sum in one line, and with one line of output for each line in input.
示例输入：
4 1 2 3 4
5 1 2 3 4 5
0
示例输出：
10
15提示：
参考答案（内存最优[748]）：
#include<stdio.h>
int main()
{
int a,c,d,j,i,sum;
scanf("%d",&d);
for(j=0;j<d;j++)
{
while(scanf("%d",&c)!=EOF)
{ sum=0;
for(i=0;i<c;i++)
{
scanf("%d",&a);
sum=sum+a;
}
printf("%d\n",sum);
}
}
return 0;
}
参考答案（时间最优[0]）：
#include<stdio.h>
int main()
{
int a,c,d,j,i,sum;
scanf("%d",&d);
for(j=0;j<d;j++)
{
while(scanf("%d",&c)!=EOF)
{ sum=0;
for(i=0;i<c;i++)
{
scanf("%d",&a);
sum=sum+a;
}
printf("%d\n",sum);
}
}
return 0;
}
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